Question 1176727

{{{-x+y=1}}}....eq.1
{{{x+y=11}}}.......eq.2
-------------------------------add eq.1 and eq.2 

{{{-x+y+x+y=1+11}}}.......eliminate {{{x}}}

{{{2y=12}}}

{{{y=6}}}

go to

{{{x+y=11}}}.......eq.2, substitute {{{y}}}

{{{x+6=11}}}

{{{x=11-6}}}

{{{x=5}}}


solution: {{{x=5}}}, {{{y=6}}}

or intersection point of given lines is at ({{{5}}}, {{{6}}})