Question 1176674
{{{2x^2-x+3}}}
{{{(2x-3)(x+1)}}}


Zeros are  at  {{{3/2}}} and at  {{{-1}}}.


Find the vertex point looking at x exactly in the middle of  Those two Zeros:
x would be  {{{1/4}}} and y would be {{{(2(1/4)-3)(1/4+1)=-3&1/8}}}.


Another point on the graph is  x=0, {{{y=(-3)(1)=-3}}}, or  (0,-3).


The "2" coefficient on leading term means  vertex is a minimum and parabola is concave upward.


This is enough to begin sketching the graph on your own.