Question 1176656

an equation for the line in slope-intercept form:

{{{y=mx+b}}} where {{{m}}} is a slope and {{{b}}} y-intercept

if line passing through ({{{2}}},{{{ 3}}}) and ({{{5}}}, {{{2}}}) we can use them to find a slope first

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(2-3)/(5-2)}}}

{{{m=-1/3}}}


so far we have

{{{y= -(1/3)x+b}}}........use one point to calculate {{{b}}}

{{{3= -(1/3)(2)+b}}}

{{{3=-2/3+b}}}

{{{3+2/3=b}}}

{{{b=11/3}}}


your equation is

{{{y= -(1/3)x+11/3}}}


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(2,3,.12),locate(2,3,p(2,3)),
circle(5,2,.12),locate(5,2,p(5,2)),
 graph( 600, 600, -10, 10, -10, 10, -(1/3)x+11/3)) }}}