Question 110321
7x+9y=26
x=32-6y
Solve for y and x

    we have to find the values of x&y  so we will use ellimination method

     7x+9y = 26......(1)

     x+6y = 32.......(2)  {got by transfering 6y to left hand side}

  multiply (2) by 7 and subtract (1)  & (3)  hence (2) becomes 7x+42y= 224..(3)

   subtracting 1& 3 we get -33y = -198  or y = -198/-33 = 6

   substitute for y in (2) we get  x = 32- 6(6) = 32-36 = -4

    therefore the values of x& y are x = -4 and y = 6