Question 1176632
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Hi
the vertex form of a Parabola opening right(a>0) or left(a<0), 
{{{x=a(y-k)^2 +h}}}
where(h,k) is the vertex and y = k is the Line of Symmetry,
the focus is (h +p,k ), With Directrix x = (h - p) , a = 1/(4p)

V(0,0) F(-3/2,0)  Opens Left:  p = {{{1/(4a) = -3/2}}}  a = (-1/6)

x = (-1/6)y^2, the vertex form of a Parabola
Wish You the Best in your Studies.

{{{drawing(300,300,   -6, 6, -6, 6, grid(1), blue(line(1.5,6,1.5,-6)) ,
circle(-3/2,0, 0.3),
circle(0,0, 0.3),
graph( 300, 300, -6, 6, -6, 6,0,sqrt(-6x), -sqrt(-6x))) }}}

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