Question 1176632
vertex at the origin-> {{{h=0}}} and {{{k=0}}}

Focus: ({{{-3/2}}}, {{{0}}}) -> parabola opens sideways to the left

so you need

{{{y^2 = 4ax}}} form 

given {{{-3/2}}}

we get {{{y^2 = 4 (-3/2) x}}} 

 {{{y^2 = 2 (-3) x}}}

 {{{y^2 = -6x}}}

{{{drawing( 600, 600, -10, 10, -10, 10,
circle(-3/2,0,.12),locate(-3/2,0.9,F(-3/2,0)),
 graph( 600, 600, -10, 10, -10, 10, sqrt(-6x),-sqrt(-6x))) }}}