<PRE><B>Question 1176585</B>
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Hi

n = 1200, p = .40 
95% confidence interval
ME = {{{z*sqrt((p(1-p))/n)}}}
ME = {{{1.96*sqrt((.4(.6))/1200)}}} = .0277
 .40 -.028 &lt; p &lt; .40 +.028
  (.37 , .43)

Wish You the Best in your Studies.
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