Question 1176599
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A basket contains a dozen red roses and two dozen tulips. 
If two flowers will be selected one after the other with replacement, 
find the probability of getting a red rose and a tulip.
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            The solution by @ewatrrr is incorrect.


            I came to bring the correct solution.



<pre>
In all, there are 12 + 2*12 = 36 flowers.


P(1st is red rose, 2nd is tulip) = {{{(12/36)*(24/35)}}} = {{{(1/3)*(24/35)}}} = {{{8/35}}}


P(1st is tulip, 2nd is red rose) = {{{(24/36)*(12/35)}}} = {{{(2/3)*(12/35)}}} = {{{8/35}}}


P(getting a red rose and a tulip) = P(1st is red rose, 2nd is tulip)  + P(1st is tulip, 2nd is red rose) = 


    = {{{8/35}}} + {{{8/35}}} = {{{16/35}}} = 0.4571 (rounded).    <U>ANSWER</U>
</pre>

Solved.



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After seeing my post, @ewatrr made partial correction, but made another error.


Her solution in its present form still remains INCORRECT.