Question 1017128
The easiest way would be to plug in both points after finding the inverse.


y = sqrt(x^3) + 1
y - 1 = sqrt(x^3)
(y - 1)^2 = x^3
(y - 1)^(2/3) = x


g^(-1)(x) = cbrt((x - 1)^2)


g^(-1)(4) = cbrt(3^2) = cbrt(9)
g^(-1)(9) = cbrt(8^2) = 4


The point (9, 4) is on g^(-1)(x).