Question 1176546
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Hi
 d = rt 
 300 = rt  0r 300/r = t
 300 = (r+10)(t-1)
  300 = (r+10)(300/r -1 )
  300 = (r+10)((300-r)/r 
  300r = (r+10)((300-r) 
  300r = 300r + 3000 - r^2 - 10r
    r^2 + 10r + 3000 = 0
    (r+60)(r-50) = 0
            r = 50mph, the usual speed   |tossing out negative number for speed

50mph*6hr = 60mph*5hr = 300mi  checks
Wish You the Best in your Studies.
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