Question 1176533
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Let the width of the deck be *[tex \Large x], then the length of the combined pool and deck is *[tex \Large 40\ +\ 2x] and the width of the combined pool and deck is *[tex \Large 20\ +\ 2x].  The total area is the product of these two quantities, hence:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ (40\,+\,2x)(20\,+\,2x)\ =\ 1500]


Multiply the two binomials and then solve the resulting quadratic for *[tex \Large x]

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
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