Question 1176510
In General we could write an arithmetic sequence like this:

{ {{{a}}}, {{{a+d}}}, {{{a+2d}}}, {{{a+3d}}}, ... }


and formula for {{{n}}}th term


{{{a[n]=a[1]+d(n-1)}}} where {{{n}}} is the number of a term


if given {{{ a[1]=6}}} and {{{ d=7}}}


{{{6}}}th term will be

{{{a[6]=6+7(6-1)}}} 

{{{a[6]=6+7(5)}}} 

{{{a[6]=41}}} 


and {{{15}}}th term will be

{{{a[15]=6+7(15-1)}}} 

{{{a[15]=6+7(14)}}} 

{{{a[15]=104}}}