Question 1004630
(width)^2 + (length)^2 = (diagonal)^2


x^2 + (x+5)^2 = (2x - 5)^2
x^2 + x^2 + 10x + 25 = 4x^2 - 20x + 25
2x^2 + 10x + 25 = 4x^2 - 20x + 25
0 = 2x^2 - 30x
0 = 2(x)(x - 15)


x = 15 (distance can't be nonpositive)


width = x = 15
length = x + 5 = 20
diagonal = 2x - 5 = 25