Question 1176502
sec x*sin x-2 sin x=0
sin x (sec x-2)=0
sin x=0, which would be at 0 and π.
sec x=2 which is same as cos x=(1/2), which is at π/3 and 5π/3
(π/3,π,5π/3) if literally the interval is (0, 2π). If the interval is [0, 2π) ,then 0 would be allowed
{{{graph(300,300,-1,7,-1,1,(sin(x)/cos(x))-2sin(x))}}}