Question 379040
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Solve: 3 + |2y-1| ≥ 1. Graph the solution set on a number line.
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            The solution by  @Penguin is  INCORRECT.


            I came to bring you a correct solution.



<pre>
You start with this inequality


    3 + |2y-1| >= 1.


Next you subtract the number 3 from both sides.


    |2y-1| >= 1 - 3,

or

    |2y-1| >= -2.


But the absolute value is ALWAYS NON-NEGATIVE number,

so the last inequality is valid FOR ANY VALUE of y.



<U>ANSWER</U>.  The solution set is the ENTIRE NUMBER LINE from -oo to oo.
</pre>

Solved, answered, explained and completed.



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Ignore the post by &nbsp;@Pinguin, &nbsp;since it is &nbsp;&nbsp;T O T A L L Y  &nbsp;&nbsp;W R O N G.