Question 1176459
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It is the binomial type probability distribution.


The number of trial n= 20; the probability of the success trial is  {{{1/5}}},  and the number of success trial k = 2. 


    P = {{{C[20]^2*(1/5)^2*(4/5)^(20-2)}}} = {{{((20*19)/(1*2))*0.2^2*0.8^18}}} = 0.136909 = 0.137 (rounded).     <U>ANSWER</U>
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To see many other similar solved problems, look into the lessons

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