Question 1176360
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Hi
Normal distribution:
Using TI or similarly an inexpensive Casio fx-115 ES plus:
area under the standard normal distribution curve(continuous) is the same as
the Probability of the given z-score:
 P( |z|≤ -2.527) = 1 - normalcdf(-2.527, 2.527)  = 1-.9885 = .0115
Or P( |z|≤ -2.527) = 2P(z ≤ -2.527
Wish You the Best in your Studies
Shown below is the positioning of |z| = 2.527 on the Standard Normal Curve
{{{drawing(400,200,-5,5,-.5,1.5, graph(400,200,-5,5,-.5,1.5, exp(-x^2/2)), green(line(2.527,0,2.527,exp(-2.527^2/2)),line(-2.527,0,-2.527,exp(-2.527^2/2))),green(line(3,0,3,exp(-3^2/2)),line(-3,0,-3,exp(-3^2/2))),green(line( 0,0, 0,exp(0^2/2))),locate(4.8,-.01,z),locate(4.8,.2,z))}}}
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