Question 1176311
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Hi
a ≠ 0 
4ax + 5y = 28
ax + 6y = 26

4ax + 5y = 28
<u>-4ax - 24y = 26(-4)</u>    |Multiplying 2nd EQ by -4 to eliminate x
     y = (28-104)/-19 = 4   and x = 2/a     {{{ax + 24 = 26}}}

A. solution set is ( 2/a, 4)  a ≠ 0 

B. {(x,y)|x = 2/a}   a ≠ 0 

Wish You the Best in your Studies.
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