Question 1176271
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Hi
Normal Distribution:  μ = 190lbs    σ = 45
 25 passengers, gondola ...rated for a load limit of 3500 lb.  x̄ = 140lb

If:  n = 20 passengers then x̄ = 175  
 P(x̄ > 175) = 1 - P( x̄ ≤ 175)
 {{{t =blue (x - mu)/blue(sigma/sqrt(n))}}}
 t = (175 - 190)/(45/√20) = √20(-15)/45 = -1.4907
 P(x̄ > 175) = 1 - P( x̄ ≤ 175) = 1 - P( t ≤ -1.4907, df19) =  1 - .0762 = .9238

Wish You the Best in your Studies.
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