Question 1176265

{{{P(t)=P[0]*e^(rt)}}}

{{{P[0]=100}}}

{{{R= 8}}}%=>{{{r=0.08}}}
{{{t=4 }}}years

{{{P(4)=100*e^(0.08*4)}}}
{{{P(4)=100*e^(0.32)}}}
{{{P(4)=137.71}}}