Question 109955
 How would you solve {{{x^2+80=0}}} using a+bi?
:
How about this:
{{{x^2 = -80}}}
:
{{{x = sqrt(-80)}}}
:
Think of it like this, remember i^2 = -1
{{{x = sqrt(16*5*i^2)}}}
:
Extract the square roots:
{{{x = 4i*sqrt(5)}}}
:
In the a + bi form
{{{x = 0 + 4sqrt(5)i}}}