Question 1176215
a,  the first term
ar, the second term
ar^2, the third term
and then the TENTH term is ar^9.



{{{system(ar+ar^2=18,ar^9=8ar^6)}}}



Taking the second equation,  {{{(ar^9)/(8ar^6)=1}}}

{{{(1/8)r^3=1}}}

{{{r^3=2^3}}}

{{{highlight(r=2)}}}


First Term:
{{{a*2+a*2^2=18}}}
{{{2a+4a=18}}}
{{{6a=18}}}
{{{highlight(a=3)}}}
and maybe you can find the sixth term.

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