Question 962684
length of shorter leg = x


x^2 + (x+2)^2 = (x+3)^2
x^2 - 2x - 5 = 0


shorter leg = x = 1 + sqrt(6)
longer leg = x+2 = 3 + sqrt(6)
hypotenuse = x+3 = 4 + sqrt(6)