Question 1176201
here's your graph.


first is without corner points identified.
second is with corner points idenified.


<img src = "http://theo.x10hosting.com/2021/030302.jpg" >


<img src = "http://theo.x10hosting.com/2021/030303.jpg" >


the desmos.com calculator makes this easy.


you graph the opposite of the inequalities.
the feasible region is the area of the graph that is unshaded.
the corner points of the feasible region contain the max /min solution of the objective function.
that objective function was not identified in this problem.
any point in the feasible region must satisfy all the constraints.
if the inequalities are >= or <=, then the points can be on the lines themselves.