Question 1176180

When two dices are rolled , there are {{{6*6=36}}} outcomes of the type ({{{x}}},{{{y}}}), where {{{x }}}is outcome of first dice and {{{y}}} is outcome of second dice. 

As both {{{x }}}and {{{y}}} can take values from {{{1}}} to {{{6}}}, there are total {{{36}}} outcomes.

Of these the outcomes ({{{1}}},{{{5}}}), ({{{2}}},{{{4}}}), ({{{3}}},{{{3}}}), ({{{4}}},{{{2}}}) and ({{{5}}},{{{1}}}) denote we have a got a sum of{{{ 6}}}.

 Hence there are {{{5}}} outcomes (of the total of {{{36 }}}outcomes) which give us the desired output.

Hence probability of getting a sum of {{{6}}}  is {{{5/36 =0.1388888888888889 }}}or {{{13.89}}}%