Question 1176117
 Line R
{{{x+2y-1=0}}}....in slope intercept form will be
{{{2y=-x+1}}}
{{{y=-(1/2)x+1/2}}}

 line B
{{{y=mx+b}}}......given that line B 
 have the same x-intercept as line R
so find x-intercept 
{{{y=-(1/2)x+1/2}}}..........set {{{y=0}}}
{{{0=-(1/2)x+1/2}}}
{{{(1/2)x=1/2}}}
{{{x=(1/2)/(1/2)}}}
{{{x=1}}}

so the x-intercept is at the point({{{1}}},{{{0}}})

since also given that  line B passes through the point({{{3}}},{{{3}}}), we will use these two points to find a slope

{{{m=(y[2]-y[1])/(x[2]-x[1])}}}

{{{m=(3-0)/(3-1)}}}

{{{m=3/2}}}

so far equation of the line B is

{{{y=(3/2)x+b}}}...........use one point to calculate {{{b}}}

{{{3=(3/2)3+b}}}

{{{3=9/2+b}}}

{{{3-9/2=b}}}

{{{6/2-9/2=b}}}

{{{b=-3/2}}}

equation of the line B is

{{{y=(3/2)x-3/2}}}


{{{drawing( 600, 600, -10, 10, -10, 10,
circle(3,3,.12), locate(3,3,p(3,3)),locate(4,4,B),locate(-4,3,R),
 graph( 600, 600, -10, 10, -10, 10, -(1/2)x+1/2, (3/2)x-3/2)) }}}