Question 948047
Let x^(1/5) = b.


y^2 - 3y - 4 = 0

(y-4)(y+1) = 0


y = 4, y = -1


x^(1/5) = 4, x^(1/5) = -1


The "-1" solution is extraneous, so x = 4^5 = 1024.