Question 1176069


an equation of the line parallel to negative {{{6x+2y=-2}}} that passes through the point ({{{2}}}, {{{-1}}})

{{{y=mx+b}}}

recall that parallel lines have same slope, so find a slope of

{{{6x+2y=-2}}} ....solve for {{{y}}}
{{{2y=-6x-2}}} 
{{{y=-6x/2-2/2}}} 
{{{y=-3x-1}}} -> slope is {{{-3}}}

so far your line is

{{{y= -3x+b}}} ..........use given point ({{{2}}}, {{{-1}}}) to calculate {{{b}}}

{{{-1= -3*2+b}}}
{{{-1= -6+b}}}
{{{-1+6= b}}}
{{{b=5}}}


and your line is

{{{y= -3x+5}}}


check it on a graph:


{{{drawing ( 600, 600, -10, 10, -10, 10,
circle(2,-1,.12), locate(2,-1,p(2,-1)),
graph( 600, 600, -10, 10, -10, 10, -3x-1, -3x+5)) }}}