Question 1176050
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Nice problem... but you typed the equation we were supposed to prove incorrectly.<br>
{{{x/y+y/x=3}}}<br>
{{{(x^2+y^2)/(xy) = 3}}}<br>
{{{x^2+y^2 = 3xy}}}<br>
{{{x^2-2xy+y^2 = xy}}}  <-- I did that because I know, because of what we are trying to prove, that I somehow need to get from {{{x^2+y^2}}} to {{{x-y}}}<br>
{{{(x-y)^2 = xy}}}<br>
{{{log(((x-y)^2)) = log((xy))}}}<br>
{{{2*log((x-y)) = log((x))+log((y))}}}<br>
{{{log((x-y)) = (1/2)(log((x))+log((y)))}}}<br>
The factor is 1/2, not 1/3....<br>