Question 1176022
p hat =0.075, point estimate
half-interval for 95%CI iz z(0.975)*sqrt (p*(1-p)/n)
sqrt(0.075*0.925/813)=0.0092
SE=1.96*0.0092=0.0181
CI is (0.057, 0.093)
95% of many intervals will contain the the true proportion
5 will not
One doesn't know which 95, only that about 95 of them will.