Question 1176023
<font face="Times New Roman" size="+2">


Graph all four inequalities on the same set of axes.  The feasibility area is the polygon where all four solution sets overlap.


This is actually easier to visualize if you graph the OPPOSITE sense of each of the inequalities.  Then the feasibility area is where NONE of the solution sets exist.


																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
{{n}\choose{r}}
</font>