Question 1176007
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Hi
Normal Distribution:    μ = 98.6  and    σ = .58
n = 118  x̄ = 98.16
 z = (98.16 - 98.6)/.58/√110 = 1.8083 |  {{{z =blue (x - mu)/blue(sigma/sqrt(n))}}}
P(x̄ < 98.16) = P(x̄ ≤ 98.16) = P(z ≤ 1.8083) = .9647

b. results lend support the claim that 98.6 is the mean temperature.
 
Wish You the Best in your Studies.
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