Question 1095478
If a+bi is a solution of a polynomial, then a-bi is also a solution. That means that the roots of our polynomial are -1/2, 2, -i, and i.


(Here, a is a constant.)


a(x + 1/2)(x - 2)(x - i)(x + i)
a(x + 1/2)(x - 2)(x^2 + 1)
a(x^4 - 3x^3/2 - 3x/2 - 1) = y


Plug in the point (-1, 282) to find the value of a, then you can find the polynomial.