Question 1175796
mean=np=60.68 squirrels
variance=np(1-p)=60.68*0.63=38.23 squirrels^2
sd=sqrt(V)=6.18 squirrels
z < (63.5-60.68)/6.18, using the continuity correction factor for < 64
z < 2.82/6.18=0.456
probability is 0.6758