Question 110028
Find the x-intercepts.

y=x^2+5x+2
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Let y = 0 and solve for "x".
x^2+5x+2 = 0
x = [-5 +- sqrt(25-4*2)]/2

x = [-5 +- sqrt(17)]/2

x = (-5 + sqrt(17))/2 or x = (-5 - sqrt(17))/2

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{{{graph(400,300,-10,10,-10,10,x^2+5x+2)}}}
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Cheers,
Stan H.