Question 1175623
{{{r=7/(4-2cos(theta))}}}


polar equation is {{{r = ed/(1 - e*cos(theta))}}}


in our case {{{r=7/(4(1-(1/2)cos(theta)))}}}


from here eccentricity 


{{{e = 1/2}}} => {{{ellipse}}}


{{{ed = 7/4 }}}


{{{(1/2)d = 7/4}}}


{{{d=(7/4)/(1/2)}}}


{{{d = 7/2 }}}


and equation of directrix {{{x = -7/2}}}