Question 1175723
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Pay attention to spacing when you post.  Proofread your post to make sure everything in the question you are asking is there BEFORE YOU POST. (I'm shouting on purpose to get your attention).  (2x)^0 is 1 because anything raised to the zero power is 1.  You don't bother to include what power the measure of D is raised to.  Example (3x)^2 would mean *[tex \Large (3x)^2], (3x)^3 would mean *[tex \Large (3x)^3], and (3x)^{2y} would mean *[tex \Large (3x)^{2y}].  On the other hand, (3x)^ is meaningless.


It is your responsibility to make sure that you are understood.  It is unconscionably rude of you to write nonsense like you did and expect us to try to decipher your gibberish.

																
John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
*[illustration darwinfish.jpg]

From <https://www.algebra.com/cgi-bin/upload-illustration.mpl> 
I > Ø
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  
								
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