Question 1175714
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There are some 20c coins in box A and some 50c coins in box B. 
If 40 coins are transferred from A to B there will be the same amount of money in each box. 
If 24 coins are transferred from B to A there will be 9 times as much money in A as in B. 
How many coins are in each container ?
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Let A be the number of the 20c coins in box A, and

Let B be the number of the 20c coins in box A.


Then. following literally the problem's description, we can write these two equations


    A - 40*20 = B + 40*20      (1)    (second line of the problem condition, see above)

    A + 24*50 = 9*(B-24*50)    (2)    (third line of the problem condition, see above)


Or, simplifying, you can write these equations in equivalent form


    A - B =    1600            (3)     (instead of equation (1) )

    A - 9B = -12000            (4)     (instead of equation (2) )


Now subtract equation (4) from equation (3).  You will get

        8B = 13600.


It implies  B = {{{13600/8}}} = 1700.


Then from equation (3),  A = 1600 + 1700 = 3300.


<U>ANSWER</U>.  There are  3300  20c-coins in box A  and  1700  50c-coins in box B.
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Solved.