<PRE><B>Question 1175519</B>
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Hi

a) mean = 19.83 and  s = .267

99% confidence Interval
ME ={{{ z*sigma/sqrt(n)}}}
ME = 2.576(.267)/√10) =  .22

CI = 19.83 ± .22
from  19.61gm  to 20.05gm 

Wish You the Best in your Studies.
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