Question 1175643
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The formulas and the numbers are


    (a)   P(both defective) = P(1st is defective)*P(2nd is defective) = 0.03*0.03 = 0.0009.      <U>ANSWER</U>


    (b)  P(one of the two is defective) = P(1st is defective)*P(2nd is good) + P(1st is good)*P(2nd is defective) = 

             = 0.03*(1-0.03) + (1-0.03)*0.03 =  0.0582.     <U>ANSWER</U>
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