Question 1175615
let a equal the amount that A had.
let b equal the amount that B had.
let C equal the amount that C had.


yu are given that:


a = b + 52
b = 3c
c = a - 100


in the first 2 equations, replace b with 3c to get:
a = b + 52 becomes a = 3c + 52


in the third equation, replace a with 3c + 52 to get:
c = a - 100 becomes c = 3c + 52 - 100.
combine like terms to get:
c = 3c - 48
subtract c from both sides of the equation and add 48 to both sides of the equation to get:
48 = 2c
solve for c to get:
c = 24


in the equation that says b = 3c, replace c with 24 to get:
b = 3 * 24.
solve for b to get:
b = 72.


in the equation that says a = b + 52, replace b with 72 to get:
a = 72 + 52 = 124.


your now have:


a = 124
b = 72
c = 24


add then up and you have a + b + c = 220.


that's your solution.