Question 1175558
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Hi
Binomial Distribution:  p = .0046   q = .9954 and n = 500
a) expected number of mishandled bags = .0046*500 = 2.3  0r 2
b) P(x = 0) = binompdf(0, 500, .0046) = .0997
   P(x > 2) = 1 - P(x≤ 2) = 1 - binomcdf(500, .0046, 2) = 1-.5959 = .4041
c)  The general rule of thumb to use normal approximation to binomial distribution 
is that the sample size n is sufficiently large... if np ≥ 5.
Here:  np < 5
Wish You the Best in your Studies.
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