Question 1175545
The product of the dimensions is x(x^2+x-6) or x^3+x^2-6x=61
so x^+x^2-6x-61=0
x has to be at least 3
x=4.098
dimensions in in. are 4.098, 2.098, 7.098=61.02 in^3


{{{graph(300,300,-2,5,-10,50, x^3+x^2-6x-61)}}}