Question 1175465
the point ​(​{{{1}}},{{{-5}}})= ​(​{{{x}}},{{{y}}})

{{{x=1}}}
{{{y=-5}}}


{{{r=sqrt(1^2+(-5)^2)}}}

{{{r=sqrt(1+25)}}}

{{{r=sqrt(26)}}}



{{{sin(x)=y/r}}}

{{{sin(x)=-5/sqrt(26)}}}

{{{sin(x)=-5sqrt(26)/26}}}



{{{cos(x)=x/r}}}

{{{cos(x)=1/sqrt(26)}}}

{{{cos(x)=sqrt(26)/26}}}



{{{tan(x)=sin(x)/cos(x)}}}

{{{tan(x)=(-5sqrt(26)/26)/(sqrt(26)/26)}}}

{{{tan(x)=-5}}}


{{{cot(x)=cos(x)/sin(x)}}}

{{{cot(x)=(sqrt(26)/26)/(-5sqrt(26)/26)}}}

{{{cot(x)=-1/5}}}



{{{sec(x)=1/cos(x)}}}

{{{sec(x)=1/(sqrt(26)/26)}}}

{{{sec(x)=26/sqrt(26)}}}

{{{sec(x)=26sqrt(26)/26}}}

{{{sec(x)=sqrt(26)}}}



{{{csc(x)=1/sin(x)}}}

{{{csc(x)=1/(-5sqrt(26)/26)}}}

{{{csc(x)=26/(-5sqrt(26))}}}

{{{csc(x)=26sqrt(26)/(-5*26)}}}

{{{csc(x)=-sqrt(26)/5}}}