Question 16423
 FOLLOW THE METHOD GIVEN BELOW......
  {{{x^2-4x+8=0}}} x=__ Plus __ and minus__.
  using the formula {{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} we get 
    {{{x = (-(-4) +- sqrt((-4)^2-4*1*8))/(2*1) }}} 
     {{{x = (4+- sqrt(-16))/2}}} 
    (2+2i)   OR    ( 2-2i ) 
   +(2+2i)   OR   - (2i-2)