Question 1175455
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Hi
 y = {{{log(2,x) }}} and  y = 2^x 
According to the Rules of Logarithms 
 y = {{{log(2,x) }}}  ⇒  2^y = x
therefore:
y = 2^x is the Inverse of  y = {{{log(2,x) }}} Green
{{{drawing(300,300,    -10,10,-10,10,  
 grid(1),
graph( 300, 300, -10,10,-10,10,0, log(2,x), 2^x))}}}

Wish You the Best in your Studies.
*[tex \large\ \ log_b(x) \ = \ y \ \ \Rightarrow\ \ b^y = x]
*[tex \large\ \ nlog_bx = log_b(x^n) ]
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
*[tex \large\ \ log_b1 = 0]
*[tex \large\ \ log_bb = 1]

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