Question 1175416
<b><u>NOTE</u>:</b> I'm assuming this question is saying the passenger train catches the freight train 3 hours after the passenger train leaves.  (NOT 3 hours after the freight train leaves.)  That's what I'm basing the math on.
<pr>
<u>Passenger train</u>:
Distance = 3r
Rate = r
Time = 3
<pr>
<u>Freight train</u>:
Distance = 5(r - 10) = 5r - 50
Rate = r - 10
Time = 5
<pr>
5r - 50 = 3r
<pr>
2r = 50
<pr>
r = 25
<pr>
<u>Passenger train</u>:
Rate = r = <b>25</b>
<pr>
<u>Freight train</u>:
Rate = r - 10 = 25 - 10 = <b>15</b>