Question 1175350
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Hi
5 cards are simultaneously from a standard deck of 52 cards. (4 Aces)
52C5 is all the  ways of chosing 5 cards.
P(3 Aces) = {{{(4C3)(48C2)/(52C5)}}}

P(at least 3) = {{{((4C3)(48C2) +(4C4)(48C1))/(52C5)}}}
Use Your calculator
Wish You the Best in your Studies.
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