Question 1175252
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The probability getting double for one pair rolling is  &nbsp;&nbsp;{{{6/36}}} = {{{1/6}}}.


The probability getting 2 success throwing a pair 4 times is  


      {{{C[4]^2*(1/6)^2*(5/6)^2}}} = {{{6*(1/6)^2*(5/6)^2}}} = 0.115741 = 11.57%   (rounded).      <U>ANSWER</U>
</pre>

Solved.


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On rolling dice and associated problems, &nbsp;look into the lesson

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/Probability-and-statistics/Rolling-a-pair-of-fair-dice.lesson>Rolling a pair of fair dice</A> 

in this site. &nbsp;You will find there many other similar solved problems.


Also, &nbsp;you have this free of charge online textbook in ALGEBRA-II in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson>ALGEBRA-II - YOUR ONLINE TEXTBOOK</A>.


The referred lesson is the part of this online textbook under the topic &nbsp;"<U>Solved problems on Probability</U>". 



Save the link to this textbook together with its description


Free of charge online textbook in ALGEBRA-II
https://www.algebra.com/algebra/homework/complex/ALGEBRA-II-YOUR-ONLINE-TEXTBOOK.lesson


into your archive and use when it is needed.