Question 1175249
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Volume of the cylinder: area of base, times height<br>
{{{((pi)(r^2))(h) = (pi)((18/2)^2)(18) = (81)(18)(pi)}}}<br>
Volume of rectangular box: area of base, time height<br>
{{{(l*w)(h) = (27*11)(h)}}}<br>
The volume of water is the same in both containers:<br>
{{{(81)(18)(pi) = (27)(11)(h)}}}<br>
{{{h = ((81)(18)(pi))/((27)(11))}}}<br>
Simplify/evaluate/round as needed....<br>